(x-7)(x^2+5x+4)=0

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Solution for (x-7)(x^2+5x+4)=0 equation:


Simplifying
(x + -7)(x2 + 5x + 4) = 0

Reorder the terms:
(-7 + x)(x2 + 5x + 4) = 0

Reorder the terms:
(-7 + x)(4 + 5x + x2) = 0

Multiply (-7 + x) * (4 + 5x + x2)
(-7(4 + 5x + x2) + x(4 + 5x + x2)) = 0
((4 * -7 + 5x * -7 + x2 * -7) + x(4 + 5x + x2)) = 0
((-28 + -35x + -7x2) + x(4 + 5x + x2)) = 0
(-28 + -35x + -7x2 + (4 * x + 5x * x + x2 * x)) = 0
(-28 + -35x + -7x2 + (4x + 5x2 + x3)) = 0

Reorder the terms:
(-28 + -35x + 4x + -7x2 + 5x2 + x3) = 0

Combine like terms: -35x + 4x = -31x
(-28 + -31x + -7x2 + 5x2 + x3) = 0

Combine like terms: -7x2 + 5x2 = -2x2
(-28 + -31x + -2x2 + x3) = 0

Solving
-28 + -31x + -2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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